First, a nifty shortcut! The square of a number ending in 5 is almost a no-brainer.
If n is the number formed by the preceding digit/s (before the 5), get the product of n and n+1.
Then just append 25 (i.e. 5 x 5) to this product.
For example, 75
2:
7 x 8 = 56; therefore solution is 5625.
Another example, 115
2:
11 x 12 = 132; therefore solution is 13225
For other cases of squaring, the same shortcut techniques used in multiplication may be utilised.
Especially the general-purpose
Urdhva Tiryagbhyam (Vertically and Crosswise) formula.
To get the square of a number (of two or more digits), simplify by splitting it into at least two parts, a and b.
Thus (a + b)
2 =
a2 + 2ab + b2
The solution comprises three parts, neatly fitting the three boxes shown above. Just adjust for excess carry over.
- the head: a2
- the middle: crosswise multiplication and doubling a x b x 2
- the tail: b2
Here is a simple example to illustrate this technique.
23
2 = 529
The steps are:
- tail: 32 = 9, put it down in the rightmost box
- middle: 2 x 3 x 2 = 12, put down the 2 in the middle box and carry over the 1
- head: 22 = 4, plus the 1 carried over, is 5 in the left box
Another example.
108
2 = 11664
The steps are:
- tail: 82 = 64, put down the 4 and carry over the 6
- middle: 10 x 8 x 2 = 160, plus the 6 carried over, is 166; put down the 6 and carry over the 16
- head: 10 x 10 = 100, plus the 16 carried over, is 116
The same technique can be expanded upon to handle the squaring of bigger numbers too.